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Sagot :
The second equation is 3x + y = 2.
Let the other equation be of the form ax + by = c, where a, b and c are constants.
Given equation is 2x + y = 0
We have, a₁ = 2 and a₂ = 1
And b₁ = a and b₂ = b
Since, both equations have a unique solution,
∴ a₁ ÷ b₁ ≠ a₂ ÷ b₂
2 ÷ a ≠ 1 ÷ b
2b ≠ a … (1)
Also, (2, -4) is the solution of the equations, so it will satisfy the equations
2a - 4b = c
b = (2a - c)/4
Let c=2
b = (2a - 2) ÷ 4
b = 1
Now we can take any value for a and b which satisfy eq.(1)
Let a=3
b = (2(3) - 2) ÷ 4
b = 1
Thus, a = 3 and b=1 satisfy eq.(1)
Hence the second equation is 3x + y = 2
The equations are justified by keeping the values -
2x+y=0 ... (2)
3x+y=2 ... (3)
From eq.(2),
y=-2x
Putting value of y in eq. (3), we get,
3x+(-2x)=2
3x-2x=2
x=2
Now, putting x=2 in eq.(2)
2(2)+y=0
y=-4
Hence, the solution is justified.
Know more about Linear Equation with two variables: https://brainly.com/question/24085666
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