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In a photochemical process a hydroen atom absorbs a 410 nm photon and shortly thereafter it emits a 2628 nm photon. what is the change in energy for the combination of these processes?

Sagot :

tushargupta0691

0.389×10^−19J  is the change in energy for the combination of these processes.

λ1=410nm=410×10^−9m

λ2=2628nm=2628×10^−9m

E1−E2 = Energy absorbed by the atom in the process =hc[1/λ1−1/λ2]

=6.63×3[1/410−1/2628]×10^−9 = 0.389×10^−19J

We get, 0.389×10^−19J.

Energy is the quantitative property that is transferred to a body or to a bodily system, recognizable in the performance of work and in the structure of warmth and light. Energy is a conserved quantity—the regulation of conservation of energy states that strength can be transformed in form, however not created or destroyed. The unit of size for energy in the International System of Units (SI) is the joule (J).

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