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Find the largest possible area for a rectangle with base on the x-axis and both upper vertices are on the curve y=11-x^2

Sagot :

The largest area of rectangle can be A= (11√11)/√2

What is area of rectangle?

To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.

Area = l × w. l = length. w = width.

Given:

y=11-x²

Consider,

x is the length of the base

y is the vertices on the curve (width)

As, the area of a rectangle with its base on the x-axis.

So, base =2x

Then Area of rectangle

A = 2x(11-x²)

Foe maximum area, dA/dx=0

dA/dx = 22-4x²

22-4x² =0

22=4x²

11/2 = x²

x=√(11/2)

Now, Put x=√(11/2) in area

A= 2*√(11/2) ( 11-11/2)

A= √22(11/2)

A= (11√11)/√2

Learn more about area of rectangle here:

https://brainly.com/question/8663941

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