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If a quadratic function has the rule f(x)=(x-h)^2+k, what will cause a vertical translation?
Option 1: Changing the value of h
Option 2: Changing the value of k
Please help me as soon as possible, thanks.

Sagot :

facundo3141592

to apply a vertical translation we changed the value of k, which is the y-value of the vertex of the quadratic equation.

Then the correct option is the second one.

What will cause a vertical translation?

First, remember that for a general function f(x) we define a vertical translation of N units as:

g(x) = f(x) + N

  • If N > 0, the translation is upwards.
  • If N < 0, the translation is downwards.

In this case, we have the function:

f(x) = (x - h)^2 + k

If we apply a vertical translation of N units, then we get the new function:

f'(x) = (x - h)^2 + k + N

Now we have two constants, we can define:

k ' = k + N

Then the new quadratic function is:

f'(x) = (x - h)^2 + k'

So, as you can see, to apply a vertical translation we changed the value of k, which is the y-value of the vertex of the quadratic equation.

Then the correct option is the second one.

If you want to learn more about translations:

https://brainly.com/question/24850937

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