Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

On mars, the acceleration due to gravity is 3.77 m/s2. how far would a 47 g rock fall from rest in 6.5 s if the only force acting on it was the gravitational force due to mars?

Sagot :

On mars the rock that fall from rest in 6.5 s with an acceleration due to gravity of 3.77 m/s² would far a distance of: 79.64125 m

The free fall formula and the procedure we will use is:

h = (g * t²)/2

Where:

  • g = acceleration due to gravity
  • t = time
  • h = height traveled

Information of the problem:

  • g = 3.77 m/s²
  • t = 6.5 s
  • h =?

Applying final height formula we get:

h = (g * t²)/2

h = (3.77 m/s² * (6.5 s)²)/2

h = (3.77 m/s² * 42.25 s²)/2

h = 159.2525 m/2

h = 79.64125 m

What is free fall?

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

Learn more about free fall at brainly.com/question/11257529

#SPJ4

View image id1001265
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.