Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Find the area of the region that lies inside both curves. r = 9 sin(), r = 9 cos()

Sagot :

The area of the region inside both curves r = 9 sin(θ) and r = 9 cos(θ) is 11.56 square units.

What is integration?

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The curves are:

r = 9 sin(θ) and

r = 9 cos(θ)

On graphing the above curves:

From the graph:

A = (1/2)∫(9sin(θ))2dθ + (1/2)∫(9cos(θ)2dθ

The region is symmetrical about π/4,:

A = 81∫sin2(θ)dθ from 0 to π/4

After solving:

= 11.56 square unit

Thus, the area of the region inside both curves r = 9 sin(θ) and r = 9 cos(θ) is 11.56 square units.

Learn more about integration here:

brainly.com/question/18125359

#SPJ4

View image maheshpatelvVT
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.