A race car is moving at 40.0 m/s around a circular racetrack of radius 265 m. calculate the period of the motion.

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06-09-2022
Physics

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A race car is moving at 40.0 m/s around a circular racetrack of radius 265 m. calculate the period of the motion.

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id1001265 id1001265 · Answer 1 · 2022-09-08T17:39:08-04:00

The race car that is moving at 40.0 m/s around a circular racetrack of radius 265 m has a period of motion of 41.63 s

To solve this tangential velocity problem the formula and the procedure we will use is:

v = (2 * π * r) / T

Where:

v = tangential velocity
π = mathematical constant
r = radius
T = period

Information about the problem:

v = 40.0 m/s
π = 3.1416
r = 265 m
T=?

Applying the tangential velocity formula and isolating the period, we get:

v = (2 * π * r)/ T

T = (2 * π * r)/ v

T = (2 * 3.1416* 265 m) / 40.0 m/s

T = (1665.04 m) / 40.0 m/s

T = 41.63 s

What is tangential velocity?

In physics is the length of arc traveled in each unit of time in uniform circular motion. It is expressed in units of distance per time (m/s), (km/h).

Learn more about tangential velocity at: brainly.com/question/19660334

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What is tangential velocity?

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