Answered

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A 2-lb sample of an unknown liquid occupies a volume of 47.6 in.3 for the liquid determine (a) the specific volume, in ft3/lb, and (b) the density, in lb/ft3.

Sagot :

The specific volume is 0.0135 ft^3

The density is 74.07 lb/ft^3

Here,

A 2-lb sample of an unknown liquid occupies a volume of 47.6 in^3.

We have to find the specific volume and density.

What is Specific volume?

Volume is a measure of the amount of space occupied by an object.

Now,

Mass = 2 lb

Volume = 47.6 in^3

            = 0.027 ft^3

Hence, Specific volume = volume/ mass = 0.027/2 = 0.0135 ft^3

And, Density = mass/ volume = 2/ 0.027 = 74.07 lb/ft^3

So, The specific volume is 0.0135 ft^3

The density is 74.07 lb/ft^3

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