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A powerful motorcycle can accelerate from rest to 29.2 m/s in only 3.9 s. What is its average acceleration in meters per second squared?

Sagot :

56 meters have been determined as the distance traveled.

s-displacement, u-initial velocity, v-final velocity, a-acceleration, and t-time variables are equal to v=u + at and v2 = u2 + 2ass, respectively.

The motorcycle's values are as follows:

u= 0m/s

v=28m/s

t=4s

a=??

s=??

v=u +at

28= 0 + 4a

4a=28

a= 7m/s2

As a result, the typical acceleration is 7 m/s2.

displacement u2+2as, v2=s

28^2= 0^2+ (2x7s)

784= 14s

s= 784/14

s= 56

Therefore, the journey's distance was 56 meters.

Learn more about distance here-

https://brainly.com/question/15172156

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