At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Calculate the ph of a solution prepared by dilution 3.0 ml of 2.5 m hcl to a final volume of 100 ml with h2o.

Sagot :

The pH of the solution after dilution is 1.125.

HCl is hydrochloric acid. It is known by the name muriatic acid. It is among the strong acids. It has a pungent smell and is colorless. It has a molar mass of 36.4 g/mol. It's a common reagent used in pharmaceutical industries. It is also used in other industries such as textile, rubber, and metal.

The volume of HCl added to the solution = 3.0 ml

The molar concentration of HCl = 2.5 M

Let the molar concentration of the solution after dilution is x.

The volume of the diluted solution = 100 ml.

The molar concentration of the solution after dilution is,

[tex]M _{1} V _{2} = M_{2} V _{2} [/tex]

[tex]M_{2} = \frac{ M _{1} V _{2}}{V _{2} }[/tex]

[tex]M_{2} = \frac{2.5 \times 3}{100} [/tex]

[tex] = 0.075 \: M[/tex]

Thus, the molar concentration of the solution after dilution is 0.075 M.

The pH of the solution after the dilution is,

[tex][HCl] = [H ^{ + } ] = 0.075 \: M[/tex]

[tex]pH = - log [H ^{ + } ] [/tex]

[tex]pH = - log(0.075)[/tex]

[tex]pH = 1.125[/tex]

Therefore, the pH of the solution after dilution is 1.125.

To know more about hydrochloric acid, refer to the below link:

https://brainly.com/question/3637432

#SPJ4