Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

If the reaction is second order in a and first order in b, what is the rate when the initial concentration of [a] = 4.11 mol/l and that of [b] = 3.71 mol/l?

Sagot :

Answer:

New concentration of A =3 [A] Put the values we get new rate of reaction. − dtd[R]=k[3A] 2[B] Hence, the rate of reaction will increase by 9 times. (iii) Given that. New concentrations of A=2[A] New concentration of B=2[B] Plug the values we get.

Explanation:

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.