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Sagot :
The kinetic energy and the speed of the electrons ejected by light of wavelength is
- 580nm - No electrons emitted.
- 250 nm - 2.837 ev, speed of the energy is 0.9988×10⁶ m/s.
To find the Kinetic energy and speed of the electron, the given values are,
Work function of metallic Caesium - 2.14 ev.
What is photoelectric effect?
The phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation is called Photoelectric effect. When the electrons on the metal plate gets ejected when the light beam passed on the metal plate.
From the basic equation of photoelectric effect we have
hν = Φ + ½ mv²
where,
hν - hc/ λ ,is the energy of the incident radiation
Φ - work function of the metal
½ mv² - kinetic energy of the emitted electrons
Thus applying values,
1) For wavelength of 580 nanometers, we have
The energy of incident radiation equals,
6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹× 1.6 × 10 ⁻¹⁹)
=2.14 ev
Since the energy of incident radiation is lesser than or equal to the work function of the metal hence no electron's will be emitted.
2. The Kinetic energy can be,
K.E = 6.636× 10⁻³⁴× ((3× 10⁸)/(580× 10⁻⁹) - 2.14 × 1.6 × 10 ⁻¹⁹)
=2.837 ev.
Thus kinetic energy for the wavelength is 2.837 ev.
Speed of the energy can be calculated as,
υ = √2E/m = √2×2.837×1.6×10⁻¹⁹/(9.8 × 10⁻³¹)
= 0.9988×10⁶ m/s.
So, the speed of the energy is 0.9988×10⁶ m/s.
Learn more about the photoelectric effect,
https://brainly.com/question/9260704
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