bhays008
Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

The sum of three consecutive even integers (3 integers in a row) is 120.



Use the following setup and given equation to find your solution:

1st integer = x
2nd integer = x+2
3rd integer = x+4
Equation: x+(x+2)+(x+4)=120




Solve the equation above. What is the largest of the three integers?

Sagot :

Answer:

42

Step-by-step explanation:

x + x + 2 + x + 4 = 120

3x + 6 = 120

3x = 114

x = 114/3

x = 38

38, 40, 42

shubhamchouhanvrVT

The three integers are 38, 40, and 42.

What is an equation?

The equation in mathematics is the relationship between the variables and the number and establishes the relationship between the two or more variables.

Given that the sum of three consecutive even integers (3 integers in a row) is 120. The value of integers will be calculated as below:-

x + x + 2 + x + 4 = 120

3x + 6 = 120

3x = 114

x = 114/3

x = 38

1st integer = x = 38

2nd integer = x+2 = 38 + 2 =  40

3rd integer = x+4 = 38 + 4 = 42

Therefore, the three integers are 38, 40, and 42.

To know more about equations follow

brainly.com/question/14323743

#SPJ2

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.