Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
To find the mass of ore, the given values are,
The radius of the lead sphere is r = 7.0 cm,
The lead can be extracted with, η = 92.5% = 0.925 efficiency.
What is the Density?
Density is the substance's mass per unit of volume.
We know the density of lead as,
⇒ p = 11.4 g/cm³ .
The volume of the lead sphere is,
V = 4/3πr³
= 4/3π(7)³
V = 1436.7 cm³.
Mass of the lead present in the lead sphere is,
m = p . V
= 11.4 × 1436.7
= 16379 g
m = 16.379 kg
From the expression of efficiency, we calculate the mass of the ore,
η = Mass of lead obtained / Mass of the ore to be taken
0.925 = 16.379 kg / Mass of the ore to be taken
Mass of the ore to be taken = 17.707 kg
If the lead can be extracted with 92.5 efficiency, the mass of ore is required to make a lead sphere with a 7.00 cm radius is 17.707 kg.
Learn more about Lead extraction,
https://brainly.com/question/10982537
#SPJ4
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
