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Sagot :
The straight line graph, passing through points (0, 100) and (20, 400), can be described as follows;
1. y = 15•x + 100
2. The slope is first calculated, then the equation is expressed in the point and slope form
3a. A real world situation that can be modelled by the equation is the total cost of joining a gym.
3b. The x-axis represent the number of months of membership, while the y-axis represents the total cost of membership
Which method can be used to find the model linear equation?
1. Points on the graph are; (0, 100) and (20, 400)
The slope, m, is therefore;
m = (400 - 100)/(20 - 0) = 15
The equation in slope and intercept form is therefore;
y - 100 = 15•(x - 0) = 15•x
- y = 15•x + 100
2. The equation of the graph is found based on obtaining two points on the graph, from which the slope can be calculated.
The slope and intercept form is obtained from the point and slope form by making y the subject
3a. A real world example is fitness service that has a joining fee of $100 and a monthly payment of $15
3b. The labels for the x and y axis based on the above situation are;
- The x-axis represents the number of months of joining the fitness service
- The y-axis represents the total amount paid
Learn more about slope and intercept form of linear equations here;
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