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1. How would you make 100 ml of a 10 mM solution when you have 10 ml of a 2M solution?

2. How would you make 1 liter of 1X solution with a starting 50X stock?

3. Perform a serial dilution (drawing) showing how you would make 1 ml of a 1 uM solution using no more than 1 ml of a 1 M stock. ​

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You need to take 0.02 L of the stock solution and make up to the one liter mark.

What is serial dilution?

The term serial dilution has to do with the ability to prepare a solution from another. We have to determine the amount of the 2M solution to use.

1)  Thus, you would need to add 90 mL of distilled water to the 10 ml of a 2M solution to obtain the 100 ml of a 10 mM solution.

2) Using C1V1 = C2V2

C1 = Initial concentration

V1 = initial volume

C2 = final concentration

V2 = final volume

50 * v1 = 1 * 1

V 1 = 1/50 = 0.02 L

You need to take 0.02 L of the stock solution and make up to the one liter mark.

Learn more about serial dilution:https://brainly.com/question/13499062?

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