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Each leg of an isosceles triangle is twice as long as its base. Express the perimeter in terms of the length of the base.​

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adioabiola

The perimeter of the triangle in discuss expressed in terms of the length of the base as required in the task content is; Perimeter= 5x.

What is the perimeter of the isosceles triangle in terms of the length of the base?

According to the task content, it follows that the perimeter of the triangle in terms of the length of the base is to be determined.

Let x = length of the base

Therefore, length of each leg = 2x.

Therefore, since the perimeter of the triangle is the sum of all sides; it follows that we have;

Perimeter = x + 2x +2x

Perimeter = 5x.

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