mcnameemallory
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8x=2 |6x -2| please show me the first step

Sagot :

well, tis noteworthy that whenever we have an absolute value equation is really a piece-wise function in disguise, namely the absolute expression is really two in disguise.

[tex]8x=2|6x-2|\implies \cfrac{8x}{2}=|6x-2|\implies 4x=|6x-2|\implies \begin{cases} 4x=+(6x-2)\\ 4x=-(6x-2) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 4x=+(6x-2)\implies 4x=6x-2\implies 0=2x-2 \\\\\\ 2=2x\implies \cfrac{2}{2}=x\implies \boxed{1=x} \\\\[-0.35em] ~\dotfill\\\\ 4x=-(6x-2)\implies 4x=-6x+2\implies 10x=2\implies x=\cfrac{2}{10}\implies \boxed{x=\cfrac{1}{5}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x= \begin{cases} 1\\[1em] \frac{1}{5} \end{cases}~\hfill[/tex]

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