Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The solution for the given system of equations is (3,5) and (-4,12).
Given two systems of equations i.e. x+y=8 and y=[tex]x^{2}[/tex]-4 and asked to solve them.
⇒x+y=8; let's assume this equation as A
⇒ y=[tex]x^{2}[/tex]-4; let's assume this equation as B
From equation A
⇒y=8-x
From equation B
⇒y=[tex]x^{2}[/tex]-4
Equating both the values of y
⇒8-x=[tex]x^{2}[/tex]-4
⇒[tex]x^{2}[/tex]-8-4+x=0
⇒[tex]x^{2}[/tex]-12+x=0
{solving quadratic equation}
⇒[tex]x^{2}[/tex]-12+4x-3x=0 { factorizing the quadratic equation}
⇒[tex]x^{2}[/tex]+4x-3x-12=0
⇒x(x+4)-3(x+4)=0
⇒(x-3)(x+4)=0
Therefore, the value's of x=3,-4
⇒if x=3
From equation A
⇒y=8-3=5
For x=3 ; y=5
⇒if x=-4
From equation A
⇒y=8-(-4)=12
For x=-4 ; y=12
Therefore,The solution for the given system of equations is (3,5) and (-4,12).
Learn more about equation here:
https://brainly.com/question/10413253
#SPJ9
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
