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Sagot :
The final speed of cyclist is 12.27m/s
The following question can be solved using formulas of Motion on one dimension as the motion is in one dimension
We will use the formula
[tex]v^2-u^2=2aS[/tex]
where v is the final velocity
u is the initial velocity
a is the acceleration of the boat
s is the distance in meters
v^2 = 2 x a x S
= 2 x 46 x a
v^2=92a
v=[tex]\sqrt{92a}[/tex]
where a is the acceleration
Now using the formula v= u+ at
and putting value of v in the equation
[tex]\sqrt{92a}[/tex]=a x7.5
squaring both sides,
92a=56.25a^2
a=92/56.25=1.64 m/s^2
Now we know that v= 7.5 a=7..5 x 1.64 =12.27m/s
Hence her final speed is 12.27m/s
#SPJ9
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