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positivephysics
A bicyclist, initially at rest, begins pedaling and gaining speed steadily for 7.50s during
which she covers 46.0m.
PREMIUM
What was her final speed?

Sagot :

bharathparasad577

The final speed of cyclist is 12.27m/s

The following question can be solved using formulas of Motion on one dimension as the motion is in one dimension

We will use the formula

[tex]v^2-u^2=2aS[/tex]

where v is the final velocity

u is the initial velocity

a is the acceleration of the boat

s is the distance in meters

v^2 = 2 x a x S

       = 2 x 46 x a

v^2=92a

v=[tex]\sqrt{92a}[/tex]

where a is the acceleration

Now using the formula v= u+ at

and putting value of v in the equation

[tex]\sqrt{92a}[/tex]=a x7.5

squaring both sides,

92a=56.25a^2

a=92/56.25=1.64 m/s^2

Now we know that v= 7.5 a=7..5 x 1.64 =12.27m/s

Hence her final speed is 12.27m/s

#SPJ9

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