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Sagot :
Percent of gold and copper are 88.2 and 11.8
Red gold is a gold-copper alloy used to make jewelry .
Let the mass of gold be m1
Let the mass of copper be m2
We are given that m1+m2 =8.97 g
We know that volume is the ratio of mass to density
Thus
m1/d1 + m2/d2 = 0.528 cm3
where d1 and d2 is the density of gold and copper
m1/19.3 + m2/8.96 = 0.528
8.96m1 +19.3 m2 = 0.528 x 19.3 x 8.96 = 91.305
putting m1 = 8.97 - m2
8.96 ( 8.97 - m2 ) + 19.3 m2 = 91.305
80.3712 - 8.96m2 + 19.3 m2 =91.305
10.34 m2 = 91.305-80.3712
m2 = 10.9338 /10.34
=1.0537gm
m1=8.97-1.0537
=7.91gm
Therefore, percent of gold = 7.91/8.97 x 100 =88.20%
percent of copper = 100-88.2=11.8%
Therefore, percent of gold and copper are 88.2 and 11.8
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