Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
If the quadratic is y = a*x^2 + b*x + c
the coordinates of the vertex are:
x = -b/2a
y = (1/2a)*( -0.5*b^2 + c)
How to find the coordinates of the vertex?
For a quadratic equation in standard form:
y = a*x^2 + b*x + c
The x-value of the vertex is given as:
x = -b/2a
Once we get the x-value of the vertex, we can get the y-value by evaluating the quadratic equation in x = -b/2a, we will get:
y = a*(-b/2a)^2 + b*(-b/2a) + c
y = b^2/(4a) - b^2/2a + c = (1/2a)*(b^2/2 - b^2 + c)
y = (1/2a)*( -0.5*b^2 + c)
Then the coordinates of the vertex are:
x = -b/2a
y = (1/2a)*( -0.5*b^2 + c)
If you want to learn more about quadratic equations:
https://brainly.com/question/1214333
#SPJ1
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.