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Sagot :
If the quadratic is y = a*x^2 + b*x + c
the coordinates of the vertex are:
x = -b/2a
y = (1/2a)*( -0.5*b^2 + c)
How to find the coordinates of the vertex?
For a quadratic equation in standard form:
y = a*x^2 + b*x + c
The x-value of the vertex is given as:
x = -b/2a
Once we get the x-value of the vertex, we can get the y-value by evaluating the quadratic equation in x = -b/2a, we will get:
y = a*(-b/2a)^2 + b*(-b/2a) + c
y = b^2/(4a) - b^2/2a + c = (1/2a)*(b^2/2 - b^2 + c)
y = (1/2a)*( -0.5*b^2 + c)
Then the coordinates of the vertex are:
x = -b/2a
y = (1/2a)*( -0.5*b^2 + c)
If you want to learn more about quadratic equations:
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