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A ball is thrown from an initial height of 2 feet with an initial upward velocity of 38 ft/s. The ball's height h (in feet) after / seconds is given by the following.
h=2+38t-16t^2
Find all values off for which the ball's height is 16 feet.

Sagot :

The height of the ball according to the function h(t) is 16 feet after 1.92 seconds and after 0.46 seconds.

A function is defined as a expression containing one or more variables.

Technically speaking, a function is a means of linking a set of inputs to a set of outputs.

The height of the ball  at any time t is given by the function:

[tex]h(t)=-16t^2+38t+2[/tex]

Now the required height of the ball(in feet) is 16 feet. We have to find the value of t for which h(t)=16.

Let us substitute the values:

[tex]\implies h(t)=-16t^2+38t+2\\\implies 16=-16t^2+38t+2\\\implies 16t^2-38t+14=0\\\implies 8t^2-19t+7=0[/tex]

This is in the form of a quadratic equation in t.

Solving by using the quadratic formula:

We know that for a quadratic equation [tex]ax^2+bx+c=0[/tex]

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Therefore for the above quadratic equation:

[tex]t=\frac{-(-19)\pm \sqrt{(-19)^2-4(8)(7)}}{2(8)}\\t=\frac{19+\sqrt{137}}{8},t=\frac{19-\sqrt{137}}{8}\\t=1.919...,t=0.455...[/tex]

Therefore the ball reaches the height of 16 feet at times 1.92 seconds and at 0.46 seconds.

To learn more about functions:

https://brainly.com/question/12431044

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