rempillomarissa123
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D Learning Task No.2: Use the GRESA Method in solving the problem below. Show your solutions. Write your answers in your notebook. 1. What is the mass of the cart with a constant net force of 200N is exerted to accelerate from rest to a velocity of 40m/s in 10 s. C. 50 kg D. 500 kg 2. A. 0.5 kg B. 5 kg What is the acceleration of a ball with a mass of 0.40 kg is hit with a force of 16N? A. 0.4 m/s² C. 400 m/s² D. 4000 m/s² B. 40 m/s² 3. What is the external net force exerted on a 3.5 kg papaya, which is being pushed across a table and has an acceleration of 2.2 m/s² to the left? A. 7.0N to the left C. 7.7N to the left B. 7.5N to the right D. 7.7N to the right 4. What is the mass of a crate with a net force of 300N and accelerate it by 0.750 m/s²? A. 0.4 kg B. 4 kg C. 40 kg D. 400 kg​

Sagot :

bharathparasad577

GRESA method stands for given, required, equation, solution and answer.

We are required to solve the question according to the GRESA method. However, the question has multiple sub questions and hence we will solve each one of them separately.

Question 1:

Given:

Net force of 200N

initial velocity is 0 m/s

final velocity is 40 m/s

time is given to be 10 s

Required:

We are required to find the mass of the cart.

Equation:

By using Newton's second law of motion,

F= m x (v-u)/t

Solution:

By putting all the values, we get:

200N = m x ( 40 -0 ) / 10

m = 200 /4  = 50kg

Answer:

The weight of the cart is 50kg.

Hence option (c) 50kg is correct

QUESTION 2:

Given:

mass of ball = 0.4 kg

force of hitting = 16N

Required:

We are required to find the acceleration of the ball after hitting

Equation:

Using Newton's law of motion,

F = m x a

Solution:

By putting all the values, we get:

16 = 0.4 x a

a =16/0.4 = 40 m/s^2

Answer:

Hence option (B) 40 m/s^2 is the correct answer

QUESTION 3:

Given:

mass of papaya =3.5kg

acceleration of papaya = 2.2 m/s^2

Required:

We are required to find the net force applied

Equation:

Using Newton's law of motion,

F = m x a

Solution:

By putting all the values we get:

F = 3.5 x 2.2

  =7.7 N

Answer:

The external force applied is 7.7 N to the left

Question 4:

Given:

net force = 300N

acceleration = 0.750 m/s^2

Required:

We are required to find the mass of the crate

Equation:

By using Newton's second law of motion,

F= m x a

Solution:

By putting all the values, we get:

300 = m x 0.750

m = 300/0.750

    = 400kg

Answer:

Hence the weight of crate is 400kg

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