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Find the first derivative (x²+x-2)/(2x²-2).
how to find the answer using the quotient rule.​

Sagot :

facundo3141592

the first derivative of the given function is:

f'(x) = (2x²- 12x - 2)/( 2x² - 2)²

How to find the derivative?

The quotient rule says that, if f(x) = g(x)/h(x), then:

f'(x) = ( g'(x)*h(x) - g(x)*h'(x) )/h(x)²

In this case we know that:

g(x) = x² + x - 2

h(x) = 2x² - 2

The derivatives are:

g'(x) = 2x + 1

h'(x) = 4x

Replacing that we get:

f'(x) = ( g'(x)*h(x) - g(x)*h'(x) )/h(x)²

      = ( (2x + 1)*(2x² - 2) - ( x² + x - 2)*(4x) )/( 2x² - 2)²

Expanding the denominator we get:

f'(x) = ( 4x³ - 4x + 2x² - 2 - 4x³ + 4x² - 8x)/( 2x² - 2)²

f'(x) = (2x²- 12x - 2)/( 2x² - 2)²

That is the first derivative of the given function.

If you want to learn more about derivatives:

https://brainly.com/question/5313449

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