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(Forces and the Laws of Motion pg. 141; Friction) (Problem 4)
A box of books weighing 325 N moves at a constant velocity across the
floor when the box is pushed with a force of 425 N exerted downward at an
angle of 35.2° below the horizontal. Find μk between the box and the floor.


Sagot :

The coefficient of kinetic friction is determined as 0.75.

What is coefficient of friction?

The coefficient of kinetic friction is calculated by applying the newton's second law of motion.

Fsinθ - Ff = ma

where;

  • Ff is frictional force
  • θ is angle of applied force

W = mg

where;

  • m is mass of the box

m = W/g

m = 325/9.8

m = 33.2 kg

425 sin(35.2)   -  Ff = 33.2a

425 sin(35.2)   -  μW = 33.2a

at constant velocity, a = 0

425 sin(35.2)   -  μW= 0

μW = 244.98

μ = 244.98/W

μ = 244.98/325

μ = 0.75

Thus, the coefficient of kinetic friction is 0.75.

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