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10
5
4
3
2
4-
-6-5-4-3-2-1₁.
(25)
2 3
(1.-1)
(4.2)
5
X
What is the equation, in point-slope form, of the line
that is perpendicular to the given line and passes
through the point (2, 5)?
Oy+5=x+2
Oy-2 = x-5
Oy-5= -(x - 2)
Oy + 2 = −(x + 5)
27

10 5 4 3 2 4 654321 25 2 3 11 42 5 X What Is The Equation In Pointslope Form Of The Line That Is Perpendicular To The Given Line And Passes Through The Point 2 class=

Sagot :

Answer:

Step-by-step explanation:

Two lines perpendicular to each other then product of their slopes is k1*k2=-1

so you know the (1,-1) and (4,2) so the slope of known line is k1 = (2-(-1))/(4-1)

then slope of the line perpendicular to it is k2=-1/k1

then we know the linear equation y = ka + b

then we know k2 input(2,5) into the equation y = k2a + b

you can get the y- intercept

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