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Sagot :
The time taken for the car to stop is 4.5 seconds and the initial speed of the car is 76.47 ft/s.
Initial speed of the car
The initial speed of the car is calculated as follows;
v² = u² + 2as
where;
- v is the final velocity, when the car stops, v = 0
- u is the initial velocity
- a is the acceleration
- s is the distance traveled
0 = u² + 2as
0 = u² + 2(-17)(172)
0 = u² - 5858
u² = 5848
u = 76.47 ft/s
Time of motion of the car
v = u + at
0 = 76.47 - 17t
17t = 76.47
t = 4.5 seconds
Thus, the time taken for the car to stop is 4.5 seconds and the initial speed of the car is 76.47 ft/s.
Learn more about time of motion here: https://brainly.com/question/2364404
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