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Sagot :
The vertical component of the initial velocity is [tex]v_{0y}[/tex] = ( y / t ) + [ ( 1/2) gt ]
The horizontal component of the initial velocity is [tex]v_{0x}[/tex] = x / t
We know that,
x = [tex]v_{0x}[/tex] t
y = [tex]v_{0y}[/tex] t - ( 1/2) g[tex]t^{2}[/tex]
where,
x = Horizontal displacement of the object
y = Vertical displacement of the object
g = Acceleration due to gravity
t = Time of motion
For horizontal motion there is constant velocity and for vertical motion there is uniform acceleration.
The vertical component of the initial velocity is given as
y = [tex]v_{0y}[/tex] t - ( 1/2) g[tex]t^{2}[/tex]
[tex]v_{0y}[/tex] t = y + ( 1/2) g[tex]t^{2}[/tex]
[tex]v_{0y}[/tex] = ( y/t ) + ( 1/2 ) gt
The horizontal component of the initial velocity is given as
x = [tex]v_{0x}[/tex] t
[tex]v_{0x}[/tex] = x / t
A projectile motion is the motion of an object thrown in air at some angle with the horizontal.
Therefore,
The vertical component of the initial velocity is [tex]v_{0y}[/tex] = ( y / t ) + [ ( 1/2) gt ]
The horizontal component of the initial velocity is [tex]v_{0x}[/tex] = x / t
To know more about projectile motion
https://brainly.com/question/24562850
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