Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
The vertical component of the initial velocity is [tex]v_{0y}[/tex] = ( y / t ) + [ ( 1/2) gt ]
The horizontal component of the initial velocity is [tex]v_{0x}[/tex] = x / t
We know that,
x = [tex]v_{0x}[/tex] t
y = [tex]v_{0y}[/tex] t - ( 1/2) g[tex]t^{2}[/tex]
where,
x = Horizontal displacement of the object
y = Vertical displacement of the object
g = Acceleration due to gravity
t = Time of motion
For horizontal motion there is constant velocity and for vertical motion there is uniform acceleration.
The vertical component of the initial velocity is given as
y = [tex]v_{0y}[/tex] t - ( 1/2) g[tex]t^{2}[/tex]
[tex]v_{0y}[/tex] t = y + ( 1/2) g[tex]t^{2}[/tex]
[tex]v_{0y}[/tex] = ( y/t ) + ( 1/2 ) gt
The horizontal component of the initial velocity is given as
x = [tex]v_{0x}[/tex] t
[tex]v_{0x}[/tex] = x / t
A projectile motion is the motion of an object thrown in air at some angle with the horizontal.
Therefore,
The vertical component of the initial velocity is [tex]v_{0y}[/tex] = ( y / t ) + [ ( 1/2) gt ]
The horizontal component of the initial velocity is [tex]v_{0x}[/tex] = x / t
To know more about projectile motion
https://brainly.com/question/24562850
#SPJ4
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
