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A solution is 0.0480 m lif. what is the molarity of the solution if the density is 1.10 g/ml?

Sagot :

The molarity of the solution is 0.528 mol/L.

Given,

Molarity = 0.0480 LiF.

Density = 1.10 g/ml

0.0480 moles of LiF are present in 1 kg of solvent.

Mass of 0.0480 moles of LiF = 0.0480 mol × 26 g/mol = 1.248 g

Mass of the solution (m)=  1 kg (solvent) + 1.248 g(solute)

m = 1000 g + 1.248 g = 1001.248 g

Finding the volume of the solution,

Volume = Mass / density

Putting the values of mass and density, we get the volume,

Volume = 910.2254 mL or, 0.9102254 L

The molarity of the solution is the moles of the compound in one liter of solutions.

Molarity = mass of compound/ molar mass × volume(L)

By putting the values we get,

Molarity = 0.528 mol/L

Hence the molarity of the solution is 0.528 molar.

To learn more about molarity, visit: https://brainly.com/question/13127867

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