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Sagot :
The rms speed of the molecule is 200 m/s at a temperature of 300K. Then, the mass of the individual molecule is 3.11 ×10⁻²⁵ Kg.
Given,
The rms speed of the molecule (Vrms) = 200 m/s
The temperature of the molecule (T) = 300K
We have to find the mass (M) of individual molecules.
The expression for root mean square speed measures the speed of particles in a gas is given by:-
Vrms = √3KT/M
By squaring both sides we get,
(Vrms)² = 3KT/M
(200)² = 3 × 1.33 × 10 ⁻²³ × 300 / M
Or, M = 3.105 × 10⁻²⁵ Kg
Hence, the mass of the individual molecule is 3.105 × 10⁻²⁵ Kg.
The root mean square (R.M.S) speed V of the molecules of an ideal gas is given by the expression, v=sqrt(3RTM) and v=sqrt(3KTm) where R is universal gas constant, T is the absolute (Kelvin) temperature, m is the molar mass, K is Boltzmann's constant and M is the molecular mass.
To learn more about the rms speed, visit: https://brainly.com/question/14288178
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