Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

How would you calculate the percent relative abundance of cu-63 with the mass 62.9296 g and cu-65 with the mass 64.9278 g, when the average mass of cu is 63.546?

Sagot :

Dejanras

The percent relative abundance of Cu-63 is 69.15% and Cu-65 is 30.85%.

The atomic mass is the average mass of an element.

m(Cu) = 63.546 g; the average mass of copper

m(⁶³Cu) = 62.9296 g; average mass of copper-63 (Cu-63) isotope

m(⁶⁵Cu) = 64.9278 g; average mass of copper-65 (Cu-65) isotope

ω(⁶³Cu) = ?; average abundance of isotopes Cu-63

ω(⁶⁵Cu) = 1 - ω(⁶³Cu);  average abundance of isotopes Cu-65

Ar(Cu) = ω(⁶³Cu) × m(⁶³Cu) + ω(⁶⁵Cu) × m(⁶⁵Cu)

63.546 g = ω(⁶³Cu) × 62.9296 g + (1 - ω(⁶³Cu)) × 64.9278 g

63.546 = 62.9296 × ω(⁶³Cu) + 64.9278 - 64.9278 × ω(⁶³Cu)

1.9982ω(⁶³Cu) = 1.3818

ω(⁶³Cu) = 1.4738 ÷ 1.9982

ω(⁶³Cu) = 0.6915 × 100%

ω(⁶³Cu) = 69.15%

ω(⁶⁵Cu) = 100% - 69.15%

ω(⁶⁵Cu) = 30.85%

More about relative abundance: brainly.com/question/19425232

#SPJ4

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.