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How would you calculate the percent relative abundance of cu-63 with the mass 62.9296 g and cu-65 with the mass 64.9278 g, when the average mass of cu is 63.546?

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Dejanras

The percent relative abundance of Cu-63 is 69.15% and Cu-65 is 30.85%.

The atomic mass is the average mass of an element.

m(Cu) = 63.546 g; the average mass of copper

m(⁶³Cu) = 62.9296 g; average mass of copper-63 (Cu-63) isotope

m(⁶⁵Cu) = 64.9278 g; average mass of copper-65 (Cu-65) isotope

ω(⁶³Cu) = ?; average abundance of isotopes Cu-63

ω(⁶⁵Cu) = 1 - ω(⁶³Cu);  average abundance of isotopes Cu-65

Ar(Cu) = ω(⁶³Cu) × m(⁶³Cu) + ω(⁶⁵Cu) × m(⁶⁵Cu)

63.546 g = ω(⁶³Cu) × 62.9296 g + (1 - ω(⁶³Cu)) × 64.9278 g

63.546 = 62.9296 × ω(⁶³Cu) + 64.9278 - 64.9278 × ω(⁶³Cu)

1.9982ω(⁶³Cu) = 1.3818

ω(⁶³Cu) = 1.4738 ÷ 1.9982

ω(⁶³Cu) = 0.6915 × 100%

ω(⁶³Cu) = 69.15%

ω(⁶⁵Cu) = 100% - 69.15%

ω(⁶⁵Cu) = 30.85%

More about relative abundance: brainly.com/question/19425232

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