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use a scalar projection to show that the distance from a point p1sx1, y1d to the line ax 1 by 1 c − 0 is

Sagot :

According to the question, the given data for the scalar projection calculation represent the point [tex]P1(x1,y1)[/tex] to the line [tex]ax1+by1+c=0.[/tex]

What is scalar projection?

Scalar projection refers to scalar coordinates in the cartesian coordinates. It is also the length of the vector projection. It is calculated with the help of the dot product with the unit vector direction. It always tells about the magnitude of the projection.

By using scalar projection, calculate the distance from the point [tex]P1[/tex] to the line.

Here,[tex](a, b)[/tex] is perpendicular and the equation can be written as

           [tex]by1 = -ax1-c[/tex]    

          [tex]y1 = -\frac{a}{b}x1-c[/tex]

For this the slope of the given equation can be written as: [tex]-\frac{a}{b}[/tex]

And the distance is : [tex]d = \frac{|ax1+by1+c|}{\sqrt{a2+b2} }[/tex].

Therefore, the calculated distance for the given equation is:[tex]d = \frac{|ax1+by1+c|}{\sqrt{a2+b2} }[/tex]

To learn more about the scalar projection from the given link:

https://brainly.com/question/14411896

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