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For each of the functions y = f(x) described below, find f(0).
(a) x
-1
1 2
f(x)
1
2
(b) y = 12 - 2x2
(c)
-10 -
0
7

8
10
IN 2 1
-
3
3
-6
6 8 10

(a) f(0) = ㅁ

Sagot :

The values of f(0) that can be read from (a similar question in part (a) and (c)) the table, functions, and graph in the question are;

(a) f(0) = 1

(b) f(0) = 12

(c) f(0) = -2

How can the table, function, and graph be evaluated to find f(0)?

Part of the question appears missing. From a similar question online, we have;

(a) A table of values;

x: -1, 0, 1, 2, 3

y: 7, 1, 6, -3, -4

Taking the function, f(x) = y, we have;

From the above values in the table, when x = 0, y = f(0) = 1

Therefore;

  • f(0) = 1

(b) y = 12 - 2•x²

Taking the function, f(x) = y, we have;

At x = 0, y = f(0) = 12 - 2 × 0² = 12

Therefore;

  • f(0) = 12

(c) A graph of a parabola passing through the points (-1, 3), (2, -6), (5, 3)

Let f(x) = a•x² + b•x + c, represent the function, we have;

f(-1) = 3 = a•(-1)² + b•(-1) + c = a - b + c

  • 3 = a - b + c...(1)

f(2) = -6 = a•(2)² + b•(2) + c = 4•a + 2•b + c

  • -6 = 4•a + 2•b + c...(2)

f(5) = 3 = a•(5)² + b•(5) + c = 25•a + 5•b + c

  • 3 = 25•a + 5•b + c...(3)

Solving the system of linear equations, (1), (2), (3) using a graphing calculator gives;

a = 1, b = -4, c = -2

Which gives;

f(x) = x² - 4•x - 2

Therefore;

f(0) = 0² + 4×0 - 2 = -2

Which gives;

  • f(0) = -2

Learn more about evaluation of functions here:

https://brainly.com/question/27916162

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