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If there are 5.80 moles of h, how many moles of each of the compounds are present?

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[tex]Moles \: of \: H _2SO_{4} \: is \: is \: 2.9 \: moles.[/tex]

[tex]Moles \: of \: C _2H _4O _2 \: is \: 1.4 \: moles. [/tex]

[tex]Moles \: of \: NaOH\: is \: 5.8 \: moles.[/tex]

The total number of moles of hydrogen in all the compounds = 5.8 mol.

The number of hydrogen present in sulphuric acid = 2.

Let the number of moles of the sulphuric acid present

be X. [tex]Number \:of \: mol \: of H_2SO _4 \:present [/tex]

is,

[tex]1 \: mole \: of \:H _2SO_{4} \: has \: 2 \: moles \: of \: H.[/tex]

[tex]X = 5.8 \times \frac{1}{2} [/tex]

[tex]X = 2.9 \: moles[/tex]

Thus, the number of moles of sulphuric acid present is 2.9 moles.

Number of hydrogen present in acetic acid = 4

Let the number of moles of acetic acid be Y.

[tex]Number \:of \: mol \: of C _2H _4O _2 \:present [/tex]

is,

[tex]Y = 5.8 \times \frac{1}{4} [/tex]

[tex]Y = 1.4 \: moles[/tex]

Thus, the number of moles of acetic acid is 1.4 moles.

The number of hydrogen present in sodium hydroxide = 1.

Let the number of moles of sodium hydroxide be Z.

[tex]Number \:of \: mol \: of \: NaOH\:present [/tex]

is,

[tex]Z = 5.8 \times \frac{1}{1} [/tex]

[tex]Z = 5.8 \: moles[/tex]

Thus, the number of moles of sodium hydroxide is 5.8 moles.

5.8 moles. [tex]Therefore, \: moles \: of \: H _2SO_{4} \: is \: [/tex]

[tex]is \: 2.9 \: moles. \: \:Moles \: of \: C _2H _4O _2 \: is[/tex]

[tex]is \: 1.4 \: moles. \: Moles \: of \: NaOH\: is[/tex]

5.8 moles.

To know more about acetic acid, refer to the below link:

https://brainly.com/question/24194581

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