sotoliz650
Answered

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The position of the particle as a function of time is given by x(t) = e-(t - 3)2, where x is in meters and t is in seconds. What is the velocity of the particle, in meters per second, at t = 2.5 s?

Sagot :

MrRoyal

The velocity of the particle, in meters per second is 0.78 m/s

How to determine the velocity of the particle, in meters per second?

The position function is given as:

x(t) = e-(t - 3)2

Rewrite properly as

x(t) = e^-(t - 3)^2

Next, we differentiate the above function to determine the velocity function.

Using a graphing calculator, we have:

x'(t) = -2(t - 3) * e^-(t - 3)^2

At t = 2.5 s, we have:

x'(2.5) = -2(2.5 - 3) * e^-(2.5 - 3)^2

Evaluate

x'(2.5) = 0.78

Hence, the velocity of the particle, in meters per second is 0.78 m/s

Read more about velocity at

https://brainly.com/question/6504879

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