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When ethanol is exposed to pbr3, followed by magnesium, then formaldehyde, and then aqueous acid, what is the resulting product?

Sagot :

When ethanol and pbr3 combine, bromoethane and phosphoric acid are created.

PBr3+3C2H5OH------>3C2H5Br+H3PO3

The chemical name for phosphorous tribromide is PBr3. It can be created by the interaction of red phosphorous with bromine and is a Lewis acid or electron deficient chemical that lacks a complete octet. This process is quite exothermic.

It is a colorless liquid mostly utilized for changing various alcohols into their corresponding alkyl bromides. The reaction is an inverted configuration bimolecular nucleophilic substitution reaction. Alkyl bromide is the main byproduct of this process.

Alcohol attacking phosphorous tribromide triggers this reaction's mechanism, which results in the substitution of an alcohol group for a bromine atom.

     H  H      

       |  |

 H -c-c-Br  +Mg------> C2H5MgBr

       |  |

      H H

CH3MgBr = (Grignard reagent compound )

We can add a single carbon atom to make a primary alcohol by reacting a Grignard reagent with formaldehyde.

                                                                             _

CH3CH2MgBr+ H2C=O -------> CH3CH2CH2O     ----->CH3CH2OH

AQUEOUS ACID: (taking HCL as not mentioned)

CH 3 CH 2 (OH) + HCl ------> CH 3 CH 2(Cl) + H 2 O

Reaction type: double replacement

resulting product: CH 3 CH 2 Cl

To learn more substitution reaction click below-

https://brainly.com/question/10143438

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