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Sagot :
The equation for a parallel street that passes through the given point is y = 4x + 12
Equation of a line
From the question, we are to determine the equation of the street that is parallel to the first street
NOTE: Two lines are parallel if they have equal slopes.
Thus,
We will determine the slope of the first street.
From the given information,
The street passes through the points (4, 7) and (3, 3)
Using the formula,
Slope = (y₂ - y₁)/(x₂ - x₁)
x₁ = 4
y₁ = 7
x₂ = 3
y₂ = 3
∴ Slope = (3 -7)/(3 -4)
Slope = -4/-1
Slope = 4
Now,
For the equation of the parallel street
The street passes through the point (-2, 4)
Since, the street is parallel to the first street,
Slope = 4
Using the point-slope form
y - y₁ = m(x - x₁)
y - 4 = 4(x - -2)
y - 4 = 4(x + 2)
y - 4 = 4x + 8
y = 4x + 8 + 4
y = 4x + 12
Hence, the equation for a parallel street that passes through the given point is y = 4x + 12
Learn more on Equation of a line here: https://brainly.com/question/13763238
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