Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A ball is thrown upward at time t=0 from the ground with an initial velocity of 18 m/s (~ 40 mph). what is the total time it is in the air? assume that g = 10 m/s2.

Sagot :

The total time it is in the air for the ball is 3.672 s

Given:

Initial velocity = 18 m/s

We have to find the total time the ball is in the air.

By using the formula, we get,

t = v - u/a

Where t = time to reach the maximum height

v = final velocity of the ball = 0 m/s

u = initial velocity of ball = 18 m/s

a = acceleration due to gravity = -9.8

Acceleration of gravity is taken as negative because the ball is moving in the opposite direction.

t = 0 - 8/-9.8

t = 1.836 sec

Thus, time is taken by the ball to reach the ground again = time taken to reach the maximum height

So, the Total time required for the ball to reach the ground = 2t = 2 × 1.836

Total time required for the ball to reach the ground = 3.672 s

Hence, the total time it is in the air for the ball is 3.672 sec.

To learn more about time and acceleration, visit: https://brainly.com/question/13135868

#SPJ4