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Sagot :
The molarity of the Ba(NO₃)₂ solution is 0.188 M
Calculating :
Determination of the molarity of Ba(NO₃)₂
We'll begin by calculating the amount of mole of in 3.046 g of precipitate, Ba₂SO₄
Molar mass of Ba₂SO₄ = (2×137) + 32 + (4×16) = 370 g/mol
Mass of Ba₂SO₄ = 3.046 g
Mole of Ba₂SO₄ =?
Mole = mass /molar mass
Mole of Ba₂SO₄ = 3.046 / 370
Mole of Ba₂SO₄ = 0.008 mole
Next, we shall determine the amount of mole of Ba(NO₃)₂ required to produce 0.008 mole of Ba₂SO₄
Na₂SO₄(aq) + Ba(NO₃)₂(aq) —> Ba₂SO₄(s) + 2NaNO₃(aq)
From the balanced equation above,
1 mole of Ba(NO₃)₂ reacted to supply 1 mole Ba₂SO₄.
Therefore,
0.008 mole of Ba(NO₃)₂ also will react to produce 0.008 mole of Ba₂SO₄
Thus, 0.008 mole of Ba(NO₃)₂ is required for the reaction.
Finally, we shall determine the molarity of the Ba(NO₃)₂ solution
Mole of Ba(NO₃)₂ = 0.008 mole
Volume = 42.53 mL
= 42.53 / 1000
= 0.04253 L
Molarity of Ba(NO₃)₂ =?
Molarity = mole / Volume
Molarity of Ba(NO₃)₂ = 0.008 / 0.04253
Molarity of Ba(NO₃)₂ = 0.188 M
Molarity :
Molarity (M) is that the amount of a substance in a certain volume of solution. Molarity is defined because the moles of a solute per liters of a solution. Molarity is additionally known as the molar concentration of a solution
What is molarity used for?
Molarity is how chemists measure the concentration of an answer , allowing them to relate concentrations to at least one another when calculating chemical reactions and working with chemical solutions. a degree is what chemists use to refer to the amount of substance dissolved into a given amount of solution
Learn more about molarity :
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