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Write the equation of a circle for which the endpoints of a diameter are (-0,0) and (4,-6)

Sagot :

The above statement describes the equation of a circle whose endpoints of a diameter are (-0,0) and (4,-6):

(x + 2)² + (y + 3)² = 3.6

How do we calculate the formula of a circle?

The simple form equation of a circle is: (x – x1)² + (y – y1)²= r², where (x, y) are arbitrary coordinates upon that circumference of the circle, r seems to be the radius of the circle. and (x1, y1) are indeed the coordinates of the circle's center.

According to the given data:

Given points are:

(-0,0) and (4,-6)

Find that diameter's length using the locations of the locations as well as the distance formula.

d = √((x₂ - x₁)² + (y₂ - y₁)²)

  = √((4 - (-0))² + (-6 - 0)²)

 = √((4 )² + (-6 )²)

= √(16 + 36)

= √(52)

= 7.2

Radius will be r/2

7.2/2

= 3.6

To obtain the coordinates of the center, use the interest in obtaining and the midpoint formula.

[tex]C=\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}[/tex]

C = (-0 + 4)/2 , (-6 + 0)/2

C = -2 , -3

To write this circle equation, use the radius and the center coordinates.

(x - h)² + (y - h)² = r²

(x - (-2))² + (y - (-3))² = 3.6

(x + 2)² + (y + 3)² = 3.6

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