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Sagot :
The above statement describes the equation of a circle whose endpoints of a diameter are (-0,0) and (4,-6):
(x + 2)² + (y + 3)² = 3.6
How do we calculate the formula of a circle?
The simple form equation of a circle is: (x – x1)² + (y – y1)²= r², where (x, y) are arbitrary coordinates upon that circumference of the circle, r seems to be the radius of the circle. and (x1, y1) are indeed the coordinates of the circle's center.
According to the given data:
Given points are:
(-0,0) and (4,-6)
Find that diameter's length using the locations of the locations as well as the distance formula.
d = √((x₂ - x₁)² + (y₂ - y₁)²)
= √((4 - (-0))² + (-6 - 0)²)
= √((4 )² + (-6 )²)
= √(16 + 36)
= √(52)
= 7.2
Radius will be r/2
7.2/2
= 3.6
To obtain the coordinates of the center, use the interest in obtaining and the midpoint formula.
[tex]C=\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}[/tex]
C = (-0 + 4)/2 , (-6 + 0)/2
C = -2 , -3
To write this circle equation, use the radius and the center coordinates.
(x - h)² + (y - h)² = r²
(x - (-2))² + (y - (-3))² = 3.6
(x + 2)² + (y + 3)² = 3.6
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