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The equation of the line that goes through the point (2,2) and is parallel to the line going through the points (-1,6) and (1,5) can be written in the form y=mx+b where m is what and b is what?

The Equation Of The Line That Goes Through The Point 22 And Is Parallel To The Line Going Through The Points 16 And 15 Can Be Written In The Form Ymxb Where M I class=

Sagot :

sqdancefan

Answer:

  • m = -1/2
  • b = 3

Step-by-step explanation:

You want the slope-intercept equation of the line through (2, 2) and parallel to the line through (-1, 6) and (1, 5).

Slope

The parallel line will have the same slope. The slope is given by the equation ...

  m = (y2 -y1)/(x2 -x1)

  m = (5 -6)/(1 -(-1))

  m = -1/2

Intercept

We need to find the y-intercept of the desired line. Solving the equation for "b", we get ...

  y = mx +b

  b = y -mx . . . . . . . subtract mx to find b

  b = 2 -(-1/2)(2) . . . . use m=-1/2 and (x, y) = (2, 2)

  b = 2 +1

  b = 3

The equation we want is ...

  y = -1/2x +3

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