Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

The equation of the line that goes through the point (2,2) and is parallel to the line going through the points (-1,6) and (1,5) can be written in the form y=mx+b where m is what and b is what?

The Equation Of The Line That Goes Through The Point 22 And Is Parallel To The Line Going Through The Points 16 And 15 Can Be Written In The Form Ymxb Where M I class=

Sagot :

sqdancefan

Answer:

  • m = -1/2
  • b = 3

Step-by-step explanation:

You want the slope-intercept equation of the line through (2, 2) and parallel to the line through (-1, 6) and (1, 5).

Slope

The parallel line will have the same slope. The slope is given by the equation ...

  m = (y2 -y1)/(x2 -x1)

  m = (5 -6)/(1 -(-1))

  m = -1/2

Intercept

We need to find the y-intercept of the desired line. Solving the equation for "b", we get ...

  y = mx +b

  b = y -mx . . . . . . . subtract mx to find b

  b = 2 -(-1/2)(2) . . . . use m=-1/2 and (x, y) = (2, 2)

  b = 2 +1

  b = 3

The equation we want is ...

  y = -1/2x +3

View image sqdancefan
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.