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if you are given the sum of the squares of three consecutive integers, what four digits can never occur in the ones place?

Sagot :

As given the sum of squares of three consecutive integers,  four digits which never occur in the ones place are 1,3,6,8.

As given,

Let x -1 , x , x +1 are three consecutive integers.

Sum of the squares of three consecutive integers

= (x -1)² +x² + (x+1)²

= x² -2x +1 +x² +x² +2x +1

=3x² +2

Now substitute x = 0,1,2,3,4,5,6,7,8,9

Sum = 2, 5,14,29, 50, 77, 110, 149, 194, 245

Four digit never occur at ones place = 1,3,6,8

Therefore, as given the sum of squares of three consecutive integers,  four digits which never occur in the ones place are 1,3,6,8.

Learn more about integers here

brainly.com/question/15276410

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