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Sagot :
The Magnitude of the electric field intensity at the location of yellow dot will be -
E = Q/4πε₀Kr²
We have a Yellow dot situated at distance of r meters from the charge.
We have to find the magnitude of Electric field at this Yellow dot.
What is Electric Field of a Charge?
The electric field of a charge is the region around the charge in which the influence of charge's electrostatic force can be felt or measured.
According to the question -
Assume that the Yellow dot is at distance 'r' meters apart from the Point charged particle Q. Now, the Electric field intensity at the yellow dot distanced 'r' meters apart will be -
E = Q/4πε₀Kr²
The above formula will give the intensity at the yellow dot. Since the source charge is positive, therefore the direction of the electric field will be away from the charge.
Hence, the Magnitude of the electric field intensity at the location of yellow dot will be -
E = Q/4πε₀Kr²
To solve more questions on Electric field intensity, visit the link below-
https://brainly.com/question/23818773
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