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the points (0, 5) and (0, −5) are the endpoints of the diameter of a circle. the point (3, �) is on the circle, in quadrant 4. what is the value of y?

Sagot :

Using the equation of a circle, it is found that the value of y is -4.

Equation of the circle:

A circle is a closed curve that is drawn from the fixed point called the center, in which all the points on the curve are having the same distance from the center point of the center.

The equation of a circle with (h, k) center and r radius is given by:

(x-h)² + (y-k)² = r²

Given,

The points (0, 5) and (0, −5) are the endpoints of the diameter of a circle.

The point (3, y) is on the circle, in quadrant 4.

Here we need to find the value of y.

The center is the midpoint of them, thus:

[tex]x=\frac{0+0}{2}=0\\ y=\frac{5-5}{2}=0[/tex]

So, the midpoint is (0,0).

The diameter(twice the radius) is the distance between these two points, so:

[tex]2r=\sqrt{(0-0)^2+(5-(-5))^2}[/tex]

=> 2r = √0+100

=> 2r = √100

=> 2r = 10

=> r = 5

Thus, the equation of the circle is:

=> x² + y² = r²

Apply the values,

=> x² + y² = 5²

=> x² + y² = 25

The point (3,y) is on the circle, in quadrant 4. This means that:

Replacing x by 3, we can find the value of y.

Quadrant 4 means that y < 0.

Then:

=> 3² + y² = 25

=> y² = 25 - 9

=> y² = 16

=> y = ±√16

=> y = - 4

The value of y is -4.

To know more about Equation of Circle here.

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