At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
The standard error on the mean of these numbers is 1.08
For given question,
suppose your group measures the following three numbers in some experiment: 12.4,7.8,10.2
Mean of these numbers is:
[tex]\bar x=\frac{ 12.4+7.8+10.2}{3}\\\\ \bar x=10.13[/tex]
So the standard deviation would be,
[tex]\sigma=\sqrt{\frac{(12.4-10.13)^2+(7.8-10.13)^2+(10.2-10.13)^2}{3} }\\\\\sigma=1.88[/tex]
Now we find the standard error on the mean of these numbers.
[tex]\sigma_M=\frac{\sigma}{\sqrt{N} }[/tex]
where, [tex]\sigma_M[/tex] = standard error of the mean
σ = the standard deviation of the original distribution
N = the sample size
[tex]\sigma_M=\frac{1.88}{\sqrt{3} }\\\\\sigma_M=1.08[/tex]
Therefore, the standard error on the mean of these numbers is 1.08
Learn more about the standard error on the mean here:
https://brainly.com/question/14524236
#SPJ4
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
