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Sagot :
An object is released from rest on a planet that has no atmosphere. The object falls freely for 3 m in the first second.
The magnitude of acceleration due to gravity is g = 6 m/s²
How to calculate?
if we ignore air friction, height h an object falls under a gravity g is calculated through:
h =h₀ + v₀*t - 1/2*g*t²
where
t= time to reach a height h
v₀ = initial vertical velocity of the object =0 m/s( since is released from the rest)
g = gravity
h₀ = initial height = 3m
if object starts at height h₀ = 3 m then it finishes at height h= 0 m when it falls 3 meters.
then since v₀=0 m/s :
h =h₀ - 1/2*g*t²
replacing values
0 = 3 m - 1/2*g*(1 s)²
g= 2*( 3m - 0m)/(1 s)² = 6m/s²
g = 6 m/s²
What do you mean by acceleration due to gravity?
The acceleration of a body in free fall under the influence of the earth's gravity expressed as the rate of increase of velocity per unit of time and assigned the standard value of 980.665 centimeters per second per second also called g.
The acceleration of an object changes with the altitude. The change in the gravitational acceleration with distance from the center of Earth follows an inverse-square law. This means that the gravitational acceleration is inversely proportional to the square of the distance from the center of Earth. As distance is doubled, the gravitational acceleration decreases by a factor of 4. As distance is tripled, the gravitational acceleration decreases by a factor of 9, and so on.
To know more about friction visit: https://brainly.com/question/28356847
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