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if an astronaut can throw a certain wrench 14.0 m vertically upward on earth, how high could he throw it on our moon if he gives it the same starting speed in both places?

Sagot :

The formula that we will apply to get to the answer would be:

2as = v² - u²

Using this we will get the answer as 82.35425 m.

Formulation and calculation

Here,

U= initial velocity

V= final velocity

S= displacement of the body

A= acceleration of the body/ acceleration due to gravity (as per the question)

Something that has not been mentioned here but is present in the original question is that the acceleration due to gravity has been given as 0.170g.

While throwing the wrench on earth,

v² - u² = 2as

⇒[tex]u = \sqrt{v^2 - 2as}[/tex]

⇒ u = [tex]\sqrt{0-2 * -9.81 * 14}[/tex]

⇒ u= 16.57347 m/s

Since the astronaut gives the same starting speed in both the places so the u on moon would be 16.57347 m/s

While throwing the wrench on moon,

v² - u² = 2as

s = [tex]\frac{v^2 - u^2}{2a}[/tex]

⇒ s =  [tex]\frac{0^2 - 16.57347^2}{2 * (-9.81) * 0.17}[/tex]

⇒s = 82.35425 m

so, on moon, the wrench could be thrown a distance of 82.35425 m

To know more such gravity related problems, visit:

https://brainly.com/question/4939326

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