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How strong is the electric field between two parallel plates 4.4 mm apart if the potential difference between them is 220 v?

Sagot :

The electric field between the plates is 50,000 N/C.

Calculation

It is provided that the separation d between the plates is 4.4 mm and the potential difference V between the plates is 220 V.

The electric field E between the plates can be formulated as follows.

E=[tex]\frac{V}{d}[/tex]

substituting the values in the equation,

E= [tex]\frac{220}{0.0044}[/tex]

E= 50,000 N/C

Hence, we can say that the electric field between the plates is 45833.33 N/C.

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