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Sagot :
In an aquarium 2 m long, 1 m wide, and 1 m deep, the work needed to pump half of the water is 2452.5 J
Calculation
Work done is defined as the integral of force multiplied with distance.
So, the formula goes as W=[tex]\int\limits^a_b {Fx} \, dx\\[/tex]
Force can be written in terms of density as
F = m * g = ρVg
v = 2x1x1 = 2[tex]m^{3}[/tex]
so, work done will be
W = [tex]\int\limits^{0.5}_0 2*1000*9.81* {x} \, dx[/tex]
= 19620[tex](\frac{x^2}{2} )\left \{ {{0.5} \atop {0}} \right.[/tex]
W = 19620 [tex]\frac{(0.5)^2}{2}[/tex]
W= 2452.5 J
Thus, the work that is needed to be done to pump half the water = 2452.5 J
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